2. The equation for the position of equivalent-speed kinetic objects is as follows. 1 æ(t) = at + vot + æo where x() is the position, a is acceleration, t is travel time, vo is initial velocity, and...


Create a have program that has the output given in the attached photo


2. The equation for the position of equivalent-speed kinetic objects is as follows.<br>1<br>æ(t) = at + vot + æo<br>where x() is the position, a is acceleration, t is travel time, vo is initial velocity,<br>and xo is the initial position. Assume that you try to drop an object from a<br>standstill at an altitude of 1,000 meters. Complete the Java code and obtain the<br>same result as the output example. (There is no resistance in free fall, and the<br>acceleration of gravity is -9.81m/s.<br>Position after 5.00 seconds: 877.38m<br>Figure 2 Output of the Second Program<br>

Extracted text: 2. The equation for the position of equivalent-speed kinetic objects is as follows. 1 æ(t) = at + vot + æo where x() is the position, a is acceleration, t is travel time, vo is initial velocity, and xo is the initial position. Assume that you try to drop an object from a standstill at an altitude of 1,000 meters. Complete the Java code and obtain the same result as the output example. (There is no resistance in free fall, and the acceleration of gravity is -9.81m/s. Position after 5.00 seconds: 877.38m Figure 2 Output of the Second Program

Jun 09, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here