2) Slope = R le Va The figure above shows the voltage-current characteristics of a BJT and how amplification operation is obtained. For the sake of clarity, we use upper/lower case letter convention...

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Extracted text: 2) Slope = R le Va The figure above shows the voltage-current characteristics of a BJT and how amplification operation is obtained. For the sake of clarity, we use upper/lower case letter convention such that Ugg = Vgg + Upe where Vag shows the instantaneous value of the signal which is composed of a DC value Veg and AC value ve superimposed on the DC value. Through the course, we will analyze the circuits assuming the AC value is very small so that the instantaneous signal is very close to the DC value. In order words, the change of operating point values due to the AC signal is negligible. Because of that, we will use small-signal models and parameters and we will find them around the DC operating point hence we will use slope (or derivative) at that point. We call the current and voltage values at a particular DC operating point as quiescent current and quiescent voltage. "BE Remember that for a BJT in forward active region, ic = Ige VT which is the analytical expression of the given figure. Assume that we biased the BJT at the point where VE = Vae,qand le = Ic.o- Now we want to find the slope at that particular point and we call it as transconductance gm. Find the expression for gm aE lu=Vero: Your final expressions must include quiescent ic- Ice voltage/current values and it must agree with the characteristics given in the figure. Comment on how quiescent point values affect the transconductance. (If you change your Q point from left to right in the figure, how does gm change? Is this expected from the slope of the characteristics?)