2. Here is how to use the second-order Runge-Kutta Method with the same given as in fourth-order: Solve for k, and k,. k1 = hf(xn,Yn) k2 = hf(xn + h,yn + k1) and then, solve for the next value of y:...


2. Here is how to use the second-order<br>Runge-Kutta Method with the same given as<br>in fourth-order:<br>Solve for k, and k,.<br>k1 = hf(xn,Yn)<br>k2 = hf(xn + h,yn + k1)<br>and then, solve for the next value of y:<br>Yn+1 = Yn +(k1 + k2) for n = 1, 2,...<br>where x, = x, + nh.<br>Now, try to solve the initial value problem<br>y' = xy/(x² + y/2<br>with y(1) = 1 and h = 0.2 over the interval 1s<br>Xs 2 using second-order Runge-Kutta<br>Method. Solve the equation again by fourth-<br>order Runge-Kutta Method and compare<br>their results (i.e. 2nd order vs 4th order).<br>

Extracted text: 2. Here is how to use the second-order Runge-Kutta Method with the same given as in fourth-order: Solve for k, and k,. k1 = hf(xn,Yn) k2 = hf(xn + h,yn + k1) and then, solve for the next value of y: Yn+1 = Yn +(k1 + k2) for n = 1, 2,... where x, = x, + nh. Now, try to solve the initial value problem y' = xy/(x² + y/2 with y(1) = 1 and h = 0.2 over the interval 1s Xs 2 using second-order Runge-Kutta Method. Solve the equation again by fourth- order Runge-Kutta Method and compare their results (i.e. 2nd order vs 4th order).

Jun 05, 2022
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