2. An artillery shell is fired from the top of a 450-foot ridge with an initial velocity of 860 feet per second. The height of the shell after t seconds is given by the formula: y=−16t 2 + 860t + 450...

2.
An artillery shell is fired from the top of a 450-foot ridge with an initial velocity of 860 feet per second. The height of the shell after t seconds is given by the formula:

y=−16t²
+ 860t + 450

a. Find the height of the shell after 6 seconds.

b. What is the maximum height obtained by the shell?

c. When will the shell hit the ground?