2 4 5 Figure 1: Graph for Traversal /* Class representing a directed graph using adjacency lists */ static class Graph int V; //Number of Vertices LinkedList [] adj; // adjacency lists //Constructor...


Java




Pleasse add Comments and Test-Cases to code.


explore a specific way to perform a Breadth First Search (BFS) of a given Graph [ Figure 1].




2<br>4<br>5<br>Figure 1: Graph for Traversal<br>/* Class representing a directed graph using adjacency lists */<br>static class Graph<br>int V; //Number of Vertices<br>LinkedList<Integer> [] adj; // adjacency lists<br>//Constructor<br>Graph (int V)<br>{<br>this.V = V;<br>adj - new LinkedList [V];<br>for (int i = 0; i < adj.length; i++)<br>adj [i] = new LinkedList<Integer>();<br>//To add an edge to graph<br>void addEdge (int v, int w)<br>{<br>adj [v].add (w); // Add w to the list of v.<br>2<br>

Extracted text: 2 4 5 Figure 1: Graph for Traversal /* Class representing a directed graph using adjacency lists */ static class Graph int V; //Number of Vertices LinkedList [] adj; // adjacency lists //Constructor Graph (int V) { this.V = V; adj - new LinkedList [V]; for (int i = 0; i < adj.length;="" i++)="" adj="" [i]="new">(); //To add an edge to graph void addEdge (int v, int w) { adj [v].add (w); // Add w to the list of v. 2
The edges of the Graph is given to you.<br>g. addEdge (0, 1);<br>g. addEdge (0, 2);<br>g. addEdge (2, 3);<br>g. addEdge (2, 4);<br>g. addEdge (4, 5);<br>g. addEdge (1, 3);<br>g. addEdge (3, 5);<br>Your code will need to return the traversal of the nodes in BFS order, where<br>the traversal starts from Node/Vertex 0.<br>When you follow the traversal process as specified - the complexity of the solu-<br>tion will be linear as shown below.<br>Time Complexity: 0(V + E), where V is the number of Vertices and<br>E is the number of Edges respectively.<br>Space Complexity: 0(V)<br>The linear space complexity would come from the specific data structure you<br>employ to traverse the Graph using BFS.<br>

Extracted text: The edges of the Graph is given to you. g. addEdge (0, 1); g. addEdge (0, 2); g. addEdge (2, 3); g. addEdge (2, 4); g. addEdge (4, 5); g. addEdge (1, 3); g. addEdge (3, 5); Your code will need to return the traversal of the nodes in BFS order, where the traversal starts from Node/Vertex 0. When you follow the traversal process as specified - the complexity of the solu- tion will be linear as shown below. Time Complexity: 0(V + E), where V is the number of Vertices and E is the number of Edges respectively. Space Complexity: 0(V) The linear space complexity would come from the specific data structure you employ to traverse the Graph using BFS.

Jun 05, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here