2 1 7 4 and v = 6 Compute Au and Av, and compare them with b. Is it possible that at least one of u or v could be a Let A = -9 - 3 - 36 u= - 3 4 33 least-squares solution of Ax = b? (Answer this...


2<br>1<br>7<br>4<br>and v =<br>6<br>Compute Au and Av, and compare them with b. Is it possible that at least one of u or v could be a<br>Let A =<br>-9 - 3<br>- 36<br>u=<br>- 3<br>4<br>33<br>least-squares solution of Ax = b?<br>(Answer this without computing a least-squares solution.)<br>Au =<br>(Simplify your answer.)<br>Av =<br>(Simplify your answer.)<br>Compare Au and Av with b. Is it possible that at least one of u or v could be a least-squares solution of Ax = b?<br>O A. Av is closer to b than Au is. Thus, u cannot be a least-squares solution of Ax = b, but v can be.<br>O B. Au is closer to b than Av is. Thus, v cannot be a least-squares solution of Ax = b, but u can be.<br>C. Au and Av are equally close to b. Thus, both can be the least-squares solution of Ax = b.<br>O D. Au and Av are equally close to b. Thus, neither can be the least-squares solution of Ax = b.<br>

Extracted text: 2 1 7 4 and v = 6 Compute Au and Av, and compare them with b. Is it possible that at least one of u or v could be a Let A = -9 - 3 - 36 u= - 3 4 33 least-squares solution of Ax = b? (Answer this without computing a least-squares solution.) Au = (Simplify your answer.) Av = (Simplify your answer.) Compare Au and Av with b. Is it possible that at least one of u or v could be a least-squares solution of Ax = b? O A. Av is closer to b than Au is. Thus, u cannot be a least-squares solution of Ax = b, but v can be. O B. Au is closer to b than Av is. Thus, v cannot be a least-squares solution of Ax = b, but u can be. C. Au and Av are equally close to b. Thus, both can be the least-squares solution of Ax = b. O D. Au and Av are equally close to b. Thus, neither can be the least-squares solution of Ax = b.

Jun 03, 2022
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