1)Calculate [2 (8,4,-1,-2),(0,3,-5,7)],[-5(-2,3,-5,1),(3,1,-7,2)]1b)Find A^T, when A=[(1,2,0,5),(-1,3,3,9),(0,5,-8,-2)]?1c)Calculate [(1,2,1),(0,4,-1),(3,0,-3)],[(2,-1),(0,-1)(4,-1)]?1d)Determine if...

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1)Calculate [2 (8,4,-1,-2),(0,3,-5,7)],[-5(-2,3,-5,1),(3,1,-7,2)]1b)Find A^T, when A=[(1,2,0,5),(-1,3,3,9),(0,5,-8,-2)]?1c)Calculate [(1,2,1),(0,4,-1),(3,0,-3)],[(2,-1),(0,-1)(4,-1)]?1d)Determine if {[(5,-7),(-8,10)] is a span of {[(1,3),(6,-2)],[(-3,2),(1,-4)]}?1e)Determine if the set {[(1,0),(2,-2)],[(3,1),(4,1)],[(-2,5),(4,7)]}, is linearly dependent or linearly independent?

Answered Same DayDec 22, 2021

Answer To: 1)Calculate [2 (8,4,-1,-2),(0,3,-5,7)],[-5(-2,3,-5,1),(3,1,-7,2)]1b)Find A^T, when...

Robert answered on Dec 22 2021
128 Votes
Sol: 1
Solve
8 4 1 2 2 3 5 1
2 5 ,
0 3 5 7 3 1 7 2
      
   
    

If two matrices of the same order, then t
heir subtraction is defined as the matrix,
each element of which is subtract of the corresponding elements of both matrices.
Let S=
8 4 1 2 2 3 5 1
2 5 ,
0 3 5 7 3 1 7 2
      
   
    
16 8 2 4 10 15 25 5
S
0 6 10 14 15 5 35 10
26 7 23 9
15 1 25 4
S
      
    
    
  
  
 
Sol: 2
Find TA When
1 2 0 5
1 3 3 9 ,
0 5 8 2
A
 
 
 
 
   

In a given matrix A , we interchange the rows and the corresponding columns; the
new matrix obtained is called the transpose of the matrix A .
1 1 0
2 3 5
,
0 3 8
5 9 2
TA
 
 
 
 
 
 
Sol: 3
Let
1 2 1 2 1
0 4 1 0 1
3 0 3 4 1
A
   
   
  
   
       

The product of two matrices is only possible if the number of columns in first
matrix is equal to the number of rows in second matrix.
From the above two matrices,
Numbers of column in first matrix 3,
Numbers of rows in second matrix 3,
So the number of columns in first matrix is equal to the number of rows in second
matrix.
           
           
           
1 2 2 0 1 4 1 1 2 1 1 1
0 2 4 0 1 4 0 1 4 1 1 1 ,
3 2 0 0 3 4 3 1 0 1 3 1
2 0 4 1 2 1
0 0...
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