1914 0I1 au of oldizzog uelle soilgub the quadratic formula, 4a3 1 -b ±,b2 + 2 y3 27 RESTAN $7 from which y and then x can be determined. Use this method to find a root of the cubics x3 + 81x = 702...


Number 13


1914<br>0I1<br>au of oldizzog uelle<br>soilgub<br>the quadratic formula,<br>4a3<br>1<br>-b ±,b2 +<br>2<br>y3<br>27<br>RESTAN<br>$7<br>from which y and then x can be determined. Use this<br>method to find a root of the cubics x3 + 81x = 702 and<br>+6x2 +18x +13 = 0. [Hint: /142,884 = 378.]<br>IS<br>13. By making the substitution x = y +5/y, find a root of<br>the cubic equation x3= 15x 126.<br>14. Use Cardan's formula to find, in these examples of the<br>irreducible case in cubics, a root of the given equations.<br>(a) x= 63x +162<br>[Hint: 81 30/-3 = (-3 ±2/-3)3.]<br>CU<br>(b) x3= 7x +6.<br>3<br>10<br>3<br>-3<br>L21<br>(c) x6- 2x2 +5x.<br>Hint: 3 +<br>-3<br>2<br>11<br>nolo<br>-3 =<br>3<br>28 5<br>3<br>5<br>--3<br>Hint:<br>+<br>27<br>6<br>15. The great Persian poet, Omar Khayyam (circa<br>1050-1130), found a geometric solution of the cubic<br>equation x3a2x = b by using a pair of intersecting<br>conic sections. In modern notation, he first constructed<br>the parabola x2<br>diameter AC = b/a2 on the x-axis, and let P be the<br>point of intersection of the semicircle with the<br>parabola (see the figure). A perpendicular is dropped<br>= ay. Then he drew a semicircle with<br>from P to the r-axis to nroduce a nint<br>QUNCKN<br>

Extracted text: 1914 0I1 au of oldizzog uelle soilgub the quadratic formula, 4a3 1 -b ±,b2 + 2 y3 27 RESTAN $7 from which y and then x can be determined. Use this method to find a root of the cubics x3 + 81x = 702 and +6x2 +18x +13 = 0. [Hint: /142,884 = 378.] IS 13. By making the substitution x = y +5/y, find a root of the cubic equation x3= 15x 126. 14. Use Cardan's formula to find, in these examples of the irreducible case in cubics, a root of the given equations. (a) x= 63x +162 [Hint: 81 30/-3 = (-3 ±2/-3)3.] CU (b) x3= 7x +6. 3 10 3 -3 L21 (c) x6- 2x2 +5x. Hint: 3 + -3 2 11 nolo -3 = 3 28 5 3 5 --3 Hint: + 27 6 15. The great Persian poet, Omar Khayyam (circa 1050-1130), found a geometric solution of the cubic equation x3a2x = b by using a pair of intersecting conic sections. In modern notation, he first constructed the parabola x2 diameter AC = b/a2 on the x-axis, and let P be the point of intersection of the semicircle with the parabola (see the figure). A perpendicular is dropped = ay. Then he drew a semicircle with from P to the r-axis to nroduce a nint QUNCKN

Jun 04, 2022
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