19. Identify the false claim about conditional probabilities, given that P(E) > 0 and P(-E) > 0. All four claims seem valid on the first reading, but there is one impostor hiding among them. Which...

P(A|¬E), then P(E | A) > P(-E | A). (b) If P(A| E) > P(B|E) and P(A|¬E)> P(B|¬E), then P(A) > P(B). (c) If P(4| E)< p(a),="" then="" p(4|¬e)=""> P(4). (d) If P(A | E) = 0, then P(E | A) = 0. %3D "/>
Extracted text: 19. Identify the false claim about conditional probabilities, given that P(E) > 0 and P(-E) > 0. All four claims seem valid on the first reading, but there is one impostor hiding among them. Which claim do you "sus" the most? (a) If P(A| E) > P(A|¬E), then P(E | A) > P(-E | A). (b) If P(A| E) > P(B|E) and P(A|¬E)> P(B|¬E), then P(A) > P(B). (c) If P(4| E)< p(a),="" then="" p(4|¬e)=""> P(4). (d) If P(A | E) = 0, then P(E | A) = 0. %3D