17 Fit a cubic trend function to the data (- 2,11), (- 1,13), (0,13), (1,12), (2,11). Let po(t) = 1, p, (t) = t and p, (t) = t2 -2. The orthogonal cubic polynomial is pa (t) =t3 -t. The vectors for...

17<br>Fit a cubic trend function to the data (- 2,11), (- 1,13), (0,13), (1,12), (2,11). Let po(t) = 1, p, (t) = t and p, (t) = t2 -2. The orthogonal cubic polynomial is pa (t) =t3 -t. The vectors for Po, P1, and p2 are 1<br>and<br>-2<br>,respectively.<br>-1<br>---<br>

Extracted text: 17 Fit a cubic trend function to the data (- 2,11), (- 1,13), (0,13), (1,12), (2,11). Let po(t) = 1, p, (t) = t and p, (t) = t2 -2. The orthogonal cubic polynomial is pa (t) =t3 -t. The vectors for Po, P1, and p2 are 1 and -2 ,respectively. -1 ---

Jun 05, 2022

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17 Fit a cubic trend function to the data (- 2,11), (- 1,13), (0,13), (1,12), (2,11). Let po(t) = 1, p, (t) = t and p, (t) = t2 -2. The orthogonal cubic polynomial is pa (t) =t3 -t. The vectors for...

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