1:54 令 53% Find f (1), ƒ (2), ƒ (3), and ƒ (4) if ƒ (n) is defined recur- sively by f(0) = 1 and for n = 0, 1, 2, . a) f(n + 1) = f (n)+2. b) f(n + 1) — 3/ (п). c) f(n+ 1) =25m). d) f(n + 1) = f (n)²...


1:54<br>令 53%<br>Find f (1), ƒ (2), ƒ (3), and ƒ (4) if ƒ (n) is defined recur-<br>sively by f(0) = 1 and for n = 0, 1, 2, .<br>a) f(n + 1) = f (n)+2.<br>b) f(n + 1) — 3/ (п).<br>c) f(n+ 1) =25m).<br>d) f(n + 1) = f (n)² + ƒ (n) +1.<br>Find f(1), ƒ(2). f (3), ƒ (4), and f(5) if ƒ (n) is defined<br>recursively by ƒ (0) = 3 and for n = 0, 1, 2, ..<br>a) f(n + 1) = -2f(n).<br>b) f(n + 1) = 3ƒ(n) +7.<br>c) f(n + 1) = ƒ (n)² – 2ƒ (n) – 2.<br>d) f(n+ 1) ==35(m)/3¸<br>Find f(2), f(3), f(4), and f(5) if f is defined recur-<br>sively by f(0) =-1, ƒ(1) == 2, and for n = 1, 2, . .<br>a) S(n + 1) = f (n)+3ƒ (n – 1).<br>b) f(n+ 1) =f (n)²f (n – 1).<br>c) f(n+ 1) = 3ƒ (n)² – 4ƒ (n – 1)2.<br>d) f(n + 1) = f (n – 1)/f(n).<br>Find f(2), ƒ(3), S(4), and f(5) if ƒ is defined recur-<br>sively by f(0) = ƒ(1) = 1 and for n = 1, 2, ...<br>a) f(n + 1) = { (n) – S(n – 1).<br>b) f(n + 1) = f (n)f (n – 1).<br>c) ƒ(n+1) = ƒ (n)² + ƒ (n – 1)³.<br>d) f(n + 1) = S (n)/f (n – 1).<br>%3D<br>%3D<br>|<br>%3D<br>II<br>

Extracted text: 1:54 令 53% Find f (1), ƒ (2), ƒ (3), and ƒ (4) if ƒ (n) is defined recur- sively by f(0) = 1 and for n = 0, 1, 2, . a) f(n + 1) = f (n)+2. b) f(n + 1) — 3/ (п). c) f(n+ 1) =25m). d) f(n + 1) = f (n)² + ƒ (n) +1. Find f(1), ƒ(2). f (3), ƒ (4), and f(5) if ƒ (n) is defined recursively by ƒ (0) = 3 and for n = 0, 1, 2, .. a) f(n + 1) = -2f(n). b) f(n + 1) = 3ƒ(n) +7. c) f(n + 1) = ƒ (n)² – 2ƒ (n) – 2. d) f(n+ 1) ==35(m)/3¸ Find f(2), f(3), f(4), and f(5) if f is defined recur- sively by f(0) =-1, ƒ(1) == 2, and for n = 1, 2, . . a) S(n + 1) = f (n)+3ƒ (n – 1). b) f(n+ 1) =f (n)²f (n – 1). c) f(n+ 1) = 3ƒ (n)² – 4ƒ (n – 1)2. d) f(n + 1) = f (n – 1)/f(n). Find f(2), ƒ(3), S(4), and f(5) if ƒ is defined recur- sively by f(0) = ƒ(1) = 1 and for n = 1, 2, ... a) f(n + 1) = { (n) – S(n – 1). b) f(n + 1) = f (n)f (n – 1). c) ƒ(n+1) = ƒ (n)² + ƒ (n – 1)³. d) f(n + 1) = S (n)/f (n – 1). %3D %3D | %3D II

Jun 05, 2022
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