1.533O B. t 2.132OC. t>2.132D. t 1.533Calculate the value of the test statistic.t= XXXXXXXXXXRound to two decimal places as needed.)Make the appropriate conclusion. Choose the correct answer...

Extracted text: A sample of five measurements, randomly selected from a normally distributed population, resulted in the following summary statistics: x = 4.4, s = 1.4. Complete parts a through c. a. Test the null hypothesis that the mean of the population is 6 against the alternative hypothesis, µ<6. use="" a="0.10." if="" a="0.10," find="" the="" rejection="" region="" for="" the="" test.="" choose="" the="" correct="" answer="" below.="" o="" a.="" t="">1.533 O B. t< -2.132="" or="" t=""> 2.132 OC. t>2.132 D. t< -="" 1.533="" o="" e.="">< -2.132="" o="" f.="">< -="" 1.533="" or="" t=""> 1.533 Calculate the value of the test statistic. t= - 2.55 (Round to two decimal places as needed.) Make the appropriate conclusion. Choose the correct answer below. O A. Do not reject Ho. There is sufficient evidence at the a = 0.10 level of significance to conclude that the true mean of the population is less than 6. O B. Do not reject Ho. There is insufficient evidence at the a = 0.10 level of significance to conclude that the true mean of the population is less than 6. CC. Reject Ho. There is sufficient evidence at the a = 0.10 level of significance to conclude that the true mean of the population is less than 6. O D. Reject Ho. There is insufficient evidence at the a = 0.10 level of significance to conclude that the true mean of the population is less than 6. b. Test the null hypothesis that the mean of the population is 6 against the alternative hypothesis, µ# 6. Use a = 0.10.


Extracted text: If a = 0.10, find the rejection region for the test. Choose the correct answer below. O A. t< -="" 1.533="" b.="" t="">1.533 O C. t< -2.132="" o="" d.="" t="">2.132 E. t< -2.132="" or="" t=""> 2.132 OF. t< -1.533="" or="" t=""> 1.533 Calculate the value of the test statistic. t= 2.13 (Round to two decimal places as needed.)