150 MVA 150 MVA 13.8 kV Xiine = 0.12 T2 13.8 kV X6" = 0.1 T I Gen XM" = 0.25 Xo = 0.15 X2 = 0.27 X, = 0.1 Xo = 0.06 X2 = 0.12 150 MVA 150 MVA 13.8 kV A / 230 kV Y XT1 = 0.15 p.u. 230 kV Y / 13.8 kV A...

1. Draw the positive, negative and zero sequence networks and obtain the Thevenin equivalent circuits


2. Find the fault current for a single line to neutral (SLG) fault as shown in Bus 1

Extracted text: 150 MVA 150 MVA 13.8 kV Xiine = 0.12 T2 13.8 kV X6" = 0.1 T I Gen XM" = 0.25 Xo = 0.15 X2 = 0.27 X, = 0.1 Xo = 0.06 X2 = 0.12 150 MVA 150 MVA 13.8 kV A / 230 kV Y XT1 = 0.15 p.u. 230 kV Y / 13.8 kV A X72 = 0.15 p.u.