1.5 1 0.5 -0.5 -1 -1.5 -2 10 15 25 30 in Recall that for a discrete-time sinusoid, the normalized frequency, f, is the ratio of the number of cycles over the number of samples. In the plot above, what...


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1.5<br>1<br>0.5<br>-0.5<br>-1<br>-1.5<br>-2<br>10<br>15<br>25<br>30<br>in<br>Recall that for a discrete-time sinusoid, the normalized frequency, f, is the ratio of the number of cycles over<br>the number of samples. In the plot above, what is the normalized frequency expressed in decimal?<br>Answer:<br>Check<br>0.2<br>Consider a linear time invariant channel with amplitude response S(f) =<br>V1.64–1.6cos(2rf)<br>Suppose that the channel input has the form x(n)<br>4.9cos(2r0.1n) for all n from<br>-0o to +0.<br>The channel output can be written as y(n) = Acos(2r0.1n + 4) where –T < ¢ < x.<br>What is the numerical value of A? Please provide your answer<br>at least 3 significant figures.<br>Hint: Determine first the amplitude response at the frequency of the input signal x(n). Also, please check the<br>settings in your calculator. If the setting is degrees, use 180 for t; if radians then use pi button (or 3.1416).<br>Answer:<br>20<br>5<br>LO<br>

Extracted text: 1.5 1 0.5 -0.5 -1 -1.5 -2 10 15 25 30 in Recall that for a discrete-time sinusoid, the normalized frequency, f, is the ratio of the number of cycles over the number of samples. In the plot above, what is the normalized frequency expressed in decimal? Answer: Check 0.2 Consider a linear time invariant channel with amplitude response S(f) = V1.64–1.6cos(2rf) Suppose that the channel input has the form x(n) 4.9cos(2r0.1n) for all n from -0o to +0. The channel output can be written as y(n) = Acos(2r0.1n + 4) where –T < ¢="">< x.="" what="" is="" the="" numerical="" value="" of="" a?="" please="" provide="" your="" answer="" at="" least="" 3="" significant="" figures.="" hint:="" determine="" first="" the="" amplitude="" response="" at="" the="" frequency="" of="" the="" input="" signal="" x(n).="" also,="" please="" check="" the="" settings="" in="" your="" calculator.="" if="" the="" setting="" is="" degrees,="" use="" 180="" for="" t;="" if="" radians="" then="" use="" pi="" button="" (or="" 3.1416).="" answer:="" 20="" 5="">

Jun 11, 2022
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