1.4.2 y(r) = Mar(1- r|,0) %3D to show this function is not a positive definite function we use definition 1 and set n = 3 we have 72 3 | i=l j=1 i=l j=l GĞMar(1 – |r1 – r1|.0) + c&Mar(1 – |n - 2).0)...

Solve and find x's and c's such that answer will be less than zero1.4.2 y(r) = Mar(1- r|,0)<br>%3D<br>to show this function is not a positive definite function we use definition 1 and set<br>n = 3 we have<br>72<br>3<br>|<br>i=l j=1<br>i=l j=l<br>GĞMar(1 – |r1 – r1|.0)<br>+ c&Mar(1 – |n - 2).0)<br>%!<br>+ cĞMar(1 – h - r3l .0)<br>I3/,0)<br>(o ||<br>+ xÃMar(1 – |e2 - 21|.0)<br>+ cx5Mar(1= |22-12|.0)<br>– |r2 - z3|,0)<br>+ Cxci Mar(1 –|r3- z1|,0)<br>+ CsMar(1- |23 – 12|,0)<br>+ Ca¢zMar(1– |r3 – 13|,0)<br>+ xgMar(1<br>Now we take common factors<br>

Extracted text: 1.4.2 y(r) = Mar(1- r|,0) %3D to show this function is not a positive definite function we use definition 1 and set n = 3 we have 72 3 | i=l j=1 i=l j=l GĞMar(1 – |r1 – r1|.0) + c&Mar(1 – |n - 2).0) %! + cĞMar(1 – h - r3l .0) I3/,0) (o || + xÃMar(1 – |e2 - 21|.0) + cx5Mar(1= |22-12|.0) – |r2 - z3|,0) + Cxci Mar(1 –|r3- z1|,0) + CsMar(1- |23 – 12|,0) + Ca¢zMar(1– |r3 – 13|,0) + xgMar(1 Now we take common factors

Jun 04, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here
April
January
February
March
April
May
June
July
August
September
October
November
December
2025
2025
2026
2027
SunMonTueWedThuFriSat
30
31
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
1
2
3
00:00
00:30
01:00
01:30
02:00
02:30
03:00
03:30
04:00
04:30
05:00
05:30
06:00
06:30
07:00
07:30
08:00
08:30
09:00
09:30
10:00
10:30
11:00
11:30
12:00
12:30
13:00
13:30
14:00
14:30
15:00
15:30
16:00
16:30
17:00
17:30
18:00
18:30
19:00
19:30
20:00
20:30
21:00
21:30
22:00
22:30
23:00
23:30