13. х" %3-2х + 2у, у " %3D 2х - 5у; х(0) - 2, х (0) %3 3, У(0) 3 1, у (0) %3D 2 14. х " + у--101 sin(10t); у " + x%-D 101 sin(10t) ; x(0) - 0, х' (0) — 6, у(0) — 8, у' (0) - -6

Use the Laplace Transform to solve the initial value problem.
13. х

Extracted text: 13. х" %3-2х + 2у, у " %3D 2х - 5у; х(0) - 2, х (0) %3 3, У(0) 3 1, у (0) %3D 2 14. х " + у--101 sin(10t); у " + x%-D 101 sin(10t) ; x(0) - 0, х' (0) — 6, у(0) — 8, у' (0) - -6

Jun 04, 2022
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