A 0.02 kg ball is flying horizontally at 120 mps. It is struck by a force at 450 as shown. The impulse graph is given. What is the final velocity of the ball? Can you explain me in words what is done...

A 0.02 kg ball is flying horizontally at 120 mps. It is struck by a force at 45⁰ as shown. The impulse graph is given. What is the final velocity of the ball?

Can you explain me in words what is done in the solution provided at the second picture. I know it is not correct but can you explain to me where does 1000 comes from and why did it used sin45. Thank youu

Extracted text: + 120 mps 05 O.01 0.02 (577


Extracted text: 120 mps bonls -StA = mAV Area Ft - sin 46 = m Vz- V, %3D - Lo00 0-02 (v- ba) ql6. 33 nls U= 40. 33 mlg to the left