12. In a Leichtman Research Group survey of 900 TV households, 74.9% of them had at least one Internet-connected TV device (for example, Smart TV, standalone streaming device, connected video game...

Extracted text: 12. In a Leichtman Research Group survey of 900 TV households, 74.9% of them had at least one Internet-connected TV device (for example, Smart TV, standalone streaming device, connected video game console). A marketing executive wants to convey high penetration of Internet-connected TV devices, so he makes the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 77%. Test that claim using a 0.10 significance level. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. Let p denote the population proportion of all homes with at least one Internet-connected TV device. Identify the null and alternative hypotheses. Ho: p(1). H1: p (2). (Type integers or decimals. Do not round.) Identify the test statistic. z= (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. the null hypothesis. There (4). sufficient evidence to the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 77%. (3) О Аcсept (4) O is not Reject O is Fail to reject (5) warrant rejection of O support