1,14 An aireraft tow bar is positioned by means of a single hydraulic cylinder connected by a 25-mm-diameter steel rod to two identical arm-and-wheel units DEF. The mass of the entire tow bar is200...


Why are there no reaction forces of Fx and Fx at the joint F?


1,14 An aireraft tow bar is positioned by means of a single hydraulic cylinder<br>connected by a 25-mm-diameter steel rod to two identical arm-and-wheel units DEF.<br>The mass of the entire tow bar is200 kg, and its centerof gravityis located at G For-<br>the position shown, determine the normal stress in the rod.<br>Problem 1.14<br>Dimensions in mm<br>1150<br>100<br>450<br>B<br>|E<br>250<br>850<br>500<br>675<br>825<br>FREE BODY<br>ENTRE Tow BAR :<br>(200 kg)(4.81 m/s?) = 1962.0O N<br>1150 mm<br>Ax<br>+5EMA = 0 :<br>A<br>85OR<br>1150(1962.00 N)<br>R<br>850 mm<br>R = 2654,5 N<br>FREE BODY - BOTH ARM<br>WHEEL<br>UNITS:<br>tan d<br>675<br>メニ8.4270°<br>+5 EMe = 0 :<br>100 mm<br>(FeDcos x)(sso) - R(5o0) :<br>450 mm<br>Ex<br>500<br>FeD<br>550 cos 8.4270 (2654.5 N)<br>= 2439.5 N<br>(COMP.)<br>2439.5 N<br>TI (0.0125 m)?<br>S00mm ' 675mm<br>FeR<br>Aco<br>R= 2654.S KN<br>4.9697 * 1o Pa<br>4.97 MPa<br>

Extracted text: 1,14 An aireraft tow bar is positioned by means of a single hydraulic cylinder connected by a 25-mm-diameter steel rod to two identical arm-and-wheel units DEF. The mass of the entire tow bar is200 kg, and its centerof gravityis located at G For- the position shown, determine the normal stress in the rod. Problem 1.14 Dimensions in mm 1150 100 450 B |E 250 850 500 675 825 FREE BODY ENTRE Tow BAR : (200 kg)(4.81 m/s?) = 1962.0O N 1150 mm Ax +5EMA = 0 : A 85OR 1150(1962.00 N) R 850 mm R = 2654,5 N FREE BODY - BOTH ARM WHEEL UNITS: tan d 675 メニ8.4270° +5 EMe = 0 : 100 mm (FeDcos x)(sso) - R(5o0) : 450 mm Ex 500 FeD 550 cos 8.4270 (2654.5 N) = 2439.5 N (COMP.) 2439.5 N TI (0.0125 m)? S00mm ' 675mm FeR Aco R= 2654.S KN 4.9697 * 1o Pa 4.97 MPa

Jun 11, 2022
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