1.1 Problem 7.1.7 in Himmelbau An oxygen cylinder used as a standby source of oxygen contains O2 at 70°F. To calibrate the gauge on the O2 cylinder, which has a volume of 1.01 ft3, the oxygen,...

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I dont seem to get the correct answer of Pg = 1509kPa for question 1. Please can you assist me in how to approach this.

Extracted text: 1.1 Problem 7.1.7 in Himmelbau An oxygen cylinder used as a standby source of oxygen contains O2 at 70°F. To calibrate the gauge on the O2 cylinder, which has a volume of 1.01 ft3, the oxygen, initially at 70°F, is released into an evacuated tank of known volume (15.0 ft8). At equilibrium the gas pressure in the tank (and cylinder) was measured as 4 inch H20 gauge and the gas temperature in both cylinders was 75°F. A barometer in the vicinity read 29.99 inch Hg. What was the original gauge pressure of oxygen in the cylinder?


Extracted text: 02@ T: 70°F = 194. 201 K V= 1. 01ft3= 0. O LS6m bryınd er V= 15.0 ft 3 = 0.42475 m² At equilibrium : 0-99536 KPq Pabs =4-38175kAo P 4 inch HLO Tin buth ylinders :197.039 K 3. 38 639 KPa = 75° F 19.99 inch Mg %3D Patmus A Pabs = Patm + Pg- Find original Pg_of Oz in iylinder . PV- nRT PV RT P, VI RTZ Pz Vz R T2 TI P2 V2 PIVI Pz VZ => 12 Vi.TZ 1294.261)(4 38175)(0.45 3 35) (6.0286) (197.0 39) 68.81 Kpa Pg = Pabs - Patmu 68.81 M 3.38639 65.42 pa