10:51 ) & A A - O 为 26% ■ illeenisd.schoology.com 2) 3 of 10 Complete the steps by applying trig identities to show that the left hand side of the equation is equivalent to the right hand side. S =...

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10:51 ) & A A - O<br>为 26% ■<br>illeenisd.schoology.com<br>2)<br>3 of 10<br>Complete the steps by applying trig identities to show<br>that the left hand side of the equation is equivalent to<br>the right hand side.<br>S = cos<br>tan a<br>Steps:<br>sin rcos<br>tan e<br>cos z<br>sin z. cos 2<br>: sin r CONE. 0s<br>cos<br>sin<br>:: (Cusz + sin z)<br># cut r cOS E<br>sin<br>sin<br>SI<br>Sim r<br>1<br>sia a+<br>1<br>: - tan z<br>sin a<br>sin<br>coe<br>cos<br>Cos<br>sin z<br>: cot a.<br>: cot r. cot<br>sin<br>cos<br>Ki a<br>1+<br>e<br>sin z-ece z+sin<br>sin r(ms z+1)<br>Cos T<br>CO6<br>cos +1<br>Next<br>(X<br>II<br>

Extracted text: 10:51 ) & A A - O 为 26% ■ illeenisd.schoology.com 2) 3 of 10 Complete the steps by applying trig identities to show that the left hand side of the equation is equivalent to the right hand side. S = cos tan a Steps: sin rcos tan e cos z sin z. cos 2 : sin r CONE. 0s cos sin :: (Cusz + sin z) # cut r cOS E sin sin SI Sim r 1 sia a+ 1 : - tan z sin a sin coe cos Cos sin z : cot a. : cot r. cot sin cos Ki a 1+ e sin z-ece z+sin sin r(ms z+1) Cos T CO6 cos +1 Next (X II

Jun 05, 2022
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