10.37 Dissolved O, Content, continued Refer to Exercise 10.13, in which we measured the dissolved oxygen content in river water to determine whether a stream had sufficient oxygen to support aquatic...

Not sure how to do 10.3710.37 Dissolved O, Content, continued Refer to<br>Exercise 10.13, in which we measured the dissolved<br>oxygen content in river water to determine whether a<br>stream had sufficient oxygen to support aquatic life.<br>A pollution control inspector suspected that a river<br>community was releasing amounts of semitreated<br>sewage into a river. To check his theory, he drew<br>five randomly selected specimens of river water at<br>a location above the town, and another five below.<br>

Extracted text: 10.37 Dissolved O, Content, continued Refer to Exercise 10.13, in which we measured the dissolved oxygen content in river water to determine whether a stream had sufficient oxygen to support aquatic life. A pollution control inspector suspected that a river community was releasing amounts of semitreated sewage into a river. To check his theory, he drew five randomly selected specimens of river water at a location above the town, and another five below.
dissolved oxygen contents for locations above and<br>below the town. Use a 95% confidence interval.<br>The dissolved oxygen readings (in parts per million)<br>are as follows:<br>Above town<br>4.8<br>5.2<br>5.0<br>4.9<br>5.1<br>Below town<br>5.0<br>4.7<br>4.9<br>4.8<br>4.9<br>a. Do the data provide sufficient evidence to indicate<br>that the mean oxygen content below the town is less<br>than the mean oxygen content above? Test using<br>= 0.05.<br>b. Suppose you prefer estimation as a method of<br>inference. Estimate the difference in the mean<br>Data<br>to<br>

Extracted text: dissolved oxygen contents for locations above and below the town. Use a 95% confidence interval. The dissolved oxygen readings (in parts per million) are as follows: Above town 4.8 5.2 5.0 4.9 5.1 Below town 5.0 4.7 4.9 4.8 4.9 a. Do the data provide sufficient evidence to indicate that the mean oxygen content below the town is less than the mean oxygen content above? Test using = 0.05. b. Suppose you prefer estimation as a method of inference. Estimate the difference in the mean Data to

Jun 05, 2022
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