1. The strength of steel wire made by an existing process is normally distributed with a mean of 1550 and a standard deviation of 170. A batch of wire is made by a new process, and a random sample...

sbsisksnxx1. The strength of steel wire made by an existing process is normally distributed with a mean of 1550<br>and a standard deviation of 170. A batch of wire is made by a new process, and a random sample<br>consisting of 25 measurements gives an average strength of 1316. Assume that the standard<br>deviation does not change. Is there evidence at the 1% level of significance that the new process<br>gives a larger mean strength than the old? To answer this question, the null hypothesis could be<br>stated as<br>A. p = 1550 psi<br>B. p > 1550 psi<br>C. µ + 1550 psi<br>D. μ< 1550 psi<br>2. For the same problem above, which could be a statement for the alternative hypothesis?<br>A. p = 1550 psi<br>B. p > 1550 psi<br>C. µ + 1550 psi<br>D. μ< 1550 psi<br>

Extracted text: 1. The strength of steel wire made by an existing process is normally distributed with a mean of 1550 and a standard deviation of 170. A batch of wire is made by a new process, and a random sample consisting of 25 measurements gives an average strength of 1316. Assume that the standard deviation does not change. Is there evidence at the 1% level of significance that the new process gives a larger mean strength than the old? To answer this question, the null hypothesis could be stated as A. p = 1550 psi B. p > 1550 psi C. µ + 1550 psi D. μ< 1550="" psi="" 2.="" for="" the="" same="" problem="" above,="" which="" could="" be="" a="" statement="" for="" the="" alternative="" hypothesis?="" a.="" p="1550" psi="" b.="" p=""> 1550 psi C. µ + 1550 psi D. μ< 1550="">

Jun 10, 2022
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