![1: The cantilever beam below is subjected to external distributed loadings and forces between the<br>endpoints and it is in equilibrium. The left hand endpoint A is hanging free and the right hand endpoint B is built in. You<br>may assume that no external couple moments are acting on the overhanging part of the beam.<br>The figure is not to scale.<br>4 m<br>0.5 m |<br>(a)<br>The shear force diagram of the beam is shown below; V (x) = -3(x – 2.5)2 + 3 for 2.5 < a < 3.5.<br>Draw the complete free-body diagram of the beam, showing all the external forces, distributed loadings, and support<br>reactions.<br>V (kN)<br>I (m)<br>1.5<br>2.5<br>3.5<br>-1<br>(b)<br>Draw the bending moment diagram of the beam.<br>Note that the area between V and the a-axis on the interval [2.5, 3.5] is 2.<br>(c)<br>Draw the free-body diagram of the part of the beam between a = 3.5 and a = 4, i.e. the part CB.<br>](https://s3.us-east-1.amazonaws.com/storage.unifolks.com/qimg-008/008_vtjmzz0-eiaka5um.jpeg)
Extracted text: 1: The cantilever beam below is subjected to external distributed loadings and forces between the endpoints and it is in equilibrium. The left hand endpoint A is hanging free and the right hand endpoint B is built in. You may assume that no external couple moments are acting on the overhanging part of the beam. The figure is not to scale. 4 m 0.5 m | (a) The shear force diagram of the beam is shown below; V (x) = -3(x – 2.5)2 + 3 for 2.5 < a="">< 3.5.="" draw="" the="" complete="" free-body="" diagram="" of="" the="" beam,="" showing="" all="" the="" external="" forces,="" distributed="" loadings,="" and="" support="" reactions.="" v="" (kn)="" i="" (m)="" 1.5="" 2.5="" 3.5="" -1="" (b)="" draw="" the="" bending="" moment="" diagram="" of="" the="" beam.="" note="" that="" the="" area="" between="" v="" and="" the="" a-axis="" on="" the="" interval="" [2.5,="" 3.5]="" is="" 2.="" (c)="" draw="" the="" free-body="" diagram="" of="" the="" part="" of="" the="" beam="" between="" a="3.5" and="" a="4," i.e.="" the="" part="">