1 Q1) Both undergraduates and postgraduates can use the university cafeteria. Each diner can choose between buying a meal or bringing a packed lunch. (Everyone has exactly one meal each, no more and...

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Answered Same DayDec 23, 2021

Answer To: 1 Q1) Both undergraduates and postgraduates can use the university cafeteria. Each diner can choose...

David answered on Dec 23 2021
131 Votes
Solution 1:
a) P (P) = 1/5 or 0.2, P (U) = 4/5 or 0.8
P (U/M) = P (U and M)/ P (M)
P (U and B) = 0.40
P (U and M) = (1 - 0.60)* (1 -0.75) = 0.45
P (B) = 0.25
b) P (B) = 1 – P (M) = 0.75
P (M and P) =
0.2*0.75
P (M/P) = P (M and P)/ P (P)
= 0.15/0.2
= 0.75
c) P (U and B) and P (U and M) both are not equal to zero.
Solution 2:
a) We have λ =2/4 = 0.5
Using Poisson distribution,
P [X = 1] = e-λ λ x/x!
= e-0.5 (0.5) 1/1!
= 0.9098
b) P(full at midday | airport U1 bus)
= P(Airport U1 bus | full at midday) . P(full at midday) / P(airport U1 bus)
P(airport U1 bus) = P(AirportNU1 bus)
P(Airport N U1 bus) = P(Airport | U1 bus) * P(U1 bus)
P(Airport n U1 bus) = 0.5 x 0.4
=0.2
therefore P(airport U1 bus | full at midday = 0.3, P(full at midday) = 0.1
0.3 x 0.1 / 0.2 = 0.15
c) We have λ =2/4 = 0.5
Using Poisson distribution
e-λ λ n/n!= e-k
e-0.5 (0.5)n/n! = e-k
e-0.5 (0.5)n/n! = e-k
n = 1
Solution 3:
We have P ( ̅ ( 1 – 0.2 = 0.8
a) ( ̅
( ̅
( ̅

= 0.4/0.8
= 0.5
b) If P (B) = 0, then P ( ̅ which is not considered to be certainly true. P ( ̅ B) is
0.4 which indicates that event B occurs and hence cannot be zero.
c)
( ̅ ( ̅ (
0.4 *P (B)
P (B) = 0.5
( ̅
( ̅
(
= 0.4/0.8
= 0.5
d) ( ̅ ( ̅ = P (A) = 0.8 (because they are independent)
Solution 4:
a) The expected value of sample mean would be equal to the population mean i.e. 25
b) Yes, because the sample size is large.
c) Z = (X-bar - µ)/ (√σ²/n)
The respective Z-score with p > 0.1587 is 1
1 = (X-bar – 25)/ √22/n)
1 = (27 – 25)/ √22/n)
√22/n = 2
Squaring both sides, we get
22/n = 4
n = 22/4 = 5.5
d) According to chi-squared distribution, the Mean, µ = n = 25 and
Variance, σ² = 2n
2n = 22
n = 11
Solution 5:
a) We have n = 9, X-bar = 5 and s = 9
80% confidence interval is given by:-
X-bar ± t (α/2, n – 1)*s/√n
5...
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