1) #include #include M char b[] = "COMPUTER"; main() PU { char fun(int); char v; v = (char ) calloc(2, sizeof(char )); v[0] = fun(0); v[1] = fun(3); v[1][2] = '\0'; printf("%c\n", *(v[0]+2));...

can you explain this question , i just want basic experession for understanding

it is c programming data structures

1)<br>#include <stdio.h><br>#include <stdlib.h><br>M<br>char b[] =

Extracted text: 1) #include #include M char b[] = "COMPUTER"; main() PU { char *fun(int); char **v; v = (char **) calloc(2, sizeof(char *)); v[0] = fun(0); v[1] = fun(3); v[1][2] = '\0'; printf("%c\n", *(v[0]+2)); printf("%s\n", v[1]); } char *fun(int k) { return b+k; } //= II ii II %3D ii ii !!

Jun 02, 2022

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1) #include #include M char b[] = "COMPUTER"; main() PU { char fun(int); char v; v = (char ) calloc(2, sizeof(char )); v[0] = fun(0); v[1] = fun(3); v[1][2] = '\0'; printf("%c\n", *(v[0]+2));...

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1) #include #include M char b[] = "COMPUTER"; main() PU { char *fun(int); char **v; v = (char **) calloc(2, sizeof(char *)); v[0] = fun(0); v[1] = fun(3); v[1][2] = '\0'; printf("%c\n", *(v[0]+2));...

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1) #include #include M char b[] = "COMPUTER"; main() PU { char fun(int); char v; v = (char ) calloc(2, sizeof(char )); v[0] = fun(0); v[1] = fun(3); v[1][2] = '\0'; printf("%c\n", *(v[0]+2));...