1. Exploratory Data Analysis/Hypotheses a. Perform exploratory data analysis on CreativityPre and CreativityPost. Using SPSS, calculate the mean and standard deviation of these two variables. b....

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1. Exploratory Data Analysis/Hypotheses
a. Perform exploratory data analysis on CreativityPre and CreativityPost. Using SPSS, calculate the mean and standard deviation of these two variables.

b. Construct an appropriate chart/graph that displays the relevant information for these two variables.
c. Write the null and alternative hypotheses used to test the question above (e.g., whether participation in the course affects writing scores).


2. Comparison of Means
a. Perform a dependent t test to assess your hypotheses above (note that many versions of SPSS use the term “paired samples t test” rather than “dependent t test”; the test itself is the same.
b. In APA style, write one or two paragraphs that describe the dataset, gives your hypothesis, and presents the results of the dependent sample t test.



Part B. Independent t test
We will start with the data file used in Part A (“Activity 4a.sav”). Suppose, however, you [the researcher] encountered a small problem during data collection: after the post-tests were collected, you realized that the post-test form did not ask for the students’ identification number. As such, it will be impossible to match pre-test scores to post-test scores. Rather than simply give up, you start thinking about the data you do have and try to determine whether you can salvage your project. In assessing the situation, you realize that you have 40 pre-test scores and 40 post-test scores, but no way to link them. While it will result in a weaker comparison, you determine that you are still able to compare pre-test vs. post-test scores; you will use a between-subjects design rather than a within-subjects design.


1. Create the data set.
a. Using the “Activity 4a.sav” file as a starting point, create a new dataset that you can use with the between subjects design. Hint: you will no longer need the variables CreativePre and CreativeTest. Instead, you have only one variable for the score on the creativity test. A second (or grouping) variable will serve to indicate which test the student took.
b. Submit the dataset as one of the Activity 4 files.



2. Exploratory Data Analysis/Hypotheses.
a. Perform exploratory data analysis on CreativityPre and CreativityPost. Using SPSS, calculate the mean and standard deviation of these two variables.

b. Construct an appropriate chart/graph that displays the relevant information for these two variables.
c. Write the null and alternative hypotheses used to test the question above (e.g., whether participation in the course affects writing scores).


3. Comparison of Means
a. Perform an independent t test to assess your hypotheses above.
b. In APA style, write one or two paragraphs that describe the dataset, gives your hypothesis, and presents the results of the dependent sample t test.



4. Comparison of Designs
a. In this activity, you used the same dataset to analyze both a between- and within-subjects design. Create a single paragraph (using the material you wrote above), that presents both sets of results.
b. Explain, in 300-500 words, whether the two tests resulted in the same findings. Did you expect this to be the case? Why or why not? What have you learned in this activity?



Part C. ANOVA
All of us have had our blood pressure measured while at our physician’s office. How accurate are these measurements? It may surprise you to learn that there is something called “white coat syndrome”—the tendency of some people to exhibit elevated blood pressure in clinical (medical) settings only. In other words, for these people, the very fact that the physician is taking their blood pressure causes it to increase In this activity, you will be using the “Activity 4c.sav” data file to determine whether you find support for the existence of white coat syndrome. In this study, 60 participants were randomly assigned to one of three groups. The “settings” variable indicates the location in which the participants’ blood pressure was recorded: 1=home, 2=in a doctor’s office, and 3=in a classroom setting. The “SystolicBP” variable contains the participants’ systolic pressure (the “upper” number). The “DiastolicBP” variable contains the participant’s diastolic pressure (the “lower” number).


1. Exploratory Data Analysis/Hypotheses.
a. Perform exploratory data analysis on both the SystolicBP and DiastolicBP variables. Using SPSS, calculate the mean and standard deviation of these two variables. Be sure that your analysis is broken down by setting (e.g., you will have six means, six SD’s, etc.).
b. Create two graphs—one for systolic and one for diastolic pressure. Each graph should clearly delineate the three groups.
c. Write a null and alternative hypothesis for the comparison of the three groups (note that your hypothesis will state that the three groups are equivalent; be sure to word your null hypothesis correctly).


2.ANOVA.
a. Using the “Activity 4c.sav” data file, perform two single factor ANOVAs: one using SystolicBP and one using DiastolicBP as the dependent variable.
b. If appropriate for either or both of the ANOVAs, perform post hoc analyses to determine which groups actually differ.
c. Write one paragraph for each ANOVA (be sure to use APA style). At a minimum, each paragraph should contain the three means, three SD’s, ANOVA results (F, df), post hoc tests (if applicable), effect size, and an interpretation of these results.


Answered Same DayDec 23, 2021

Answer To: 1. Exploratory Data Analysis/Hypotheses a. Perform exploratory data analysis on CreativityPre and...

David answered on Dec 23 2021
125 Votes
Part A
1. .
a. .
Output of Exploratory data analysis as performed in SPSS is shown below.
Descriptive Statistics
N Range Minimu
m
Maximu
m
Mean Std.
Deviation
Varianc
e
Creativity pre-
test
40 30 26 56 40.15 8.304 68.951
Creativity post-
test
40 39 20 59 43.35 9.598 92.131
Valid N (list
wise)
40
From the above output I observe that mean and standard deviation of Pre-test is 40.15 and 8.304.
While that mean and standard deviation
of Post-test is 43.35 and 9.598.
b. .
Histogram representing mean and standard deviation for pre-test is shown below. Clearly it
follows Normal distribution.


Histogram representing mean and standard deviation for post-test is shown below. Clearly it
follows Normal distribution.
c. .
Null Hypothesis, Ho: there is no significant difference between creativity Pre-test and creativity
post-test. That is u1 – u2 = 0
Alternative Hypothesis: there is significant difference between creativity Pre-test and creativity
post-test. That is u1 – u2 is not equal to 0
2. .
a. .
Output obtained from SPSS by performing paired sample t test is shown below.
Paired Samples Statistics
Mean N Std.
Deviation
Std. Error
Mean
Pair 1
Creativity pre-
test
40.15 40 8.304 1.313
Creativity post-
test
43.35 40 9.598 1.518
Paired Samples Correlations
N Correlatio
n
Sig.
Pair 1
Creativity pre-test &
Creativity post-test
40 .650 .000
Paired Samples Test
Paired Differences t df Sig. (2-
tailed) Mean Std.
Deviation
Std.
Error
Mean
95% Confidence
Interval of the
Difference
Lower Upper
Pair
1
Creativity pre-
test - Creativity
post-test
-
3.200
7.576 1.198 -5.623 -.777
-
2.671
39 .011
b. .
Ho: there is no significant difference between creativity Pre-test and creativity post-test.
H1: there is significant difference between creativity Pre-test and creativity post-test.
Here p-value = 0.011.
Since, p-value is less than alpha (0.05), reject Ho at 5% level of significance and conclude there
is significant difference between creativity Pre-test and creativity post-test. That is u1 – u2 is not
equal to 0
Part B
.
a. .
Case summary for the rearranged data is shown below
Case Processing Summary
a

Cases
Included Excluded Total
N Percent N Percent N Percent
Creativity pre-test *
Creativity post-test
80 100.0% 0 0.0% 80 100.0%
a. Limited to first 100 cases.
Case Summaries
a

Creativity
pre-test
Creativity post-
test
Pre
1 53
2 36
3 31
4 43
5 30
6 41
7 32
8 54
9 47
10 50
11 56
12 50
13 34
14 41
15 52
16 38
17 35
18 35
19 48
20 38
21 43
22 38
23 39
24 51
25 26
26 31
27 45
28 31
29 34
30 35
31 39
32 50
33 53
34 38
35 37
36 34
37 30
38 46
39 36
40 26
Total N 40
Post
1 55
2 41
3 49
4 20
5 42
6 44
7 44
8 58
9 58
10 59
11 56
12 51
13 33
14 49
15 59
16 33
17 36
18 44
19 51
20 51
21 51
22 40
23 38
24 51
25 25
26 39
27 44
28 31
29 39
30 43
31 32
32 34
33 49
34 48
35 49
36 36
37 33
38 48
39 39
40 32
Total N 40
Total N 80
a. Limited to first 100 cases.
2. .
a. .
Exploratory data analysis showing mean and standard deviation is shown below
Descriptive Statistics
N Range Minimu
m
Maximu
m
Mean Std.
Deviation
Varianc
e
Creativity pre-
test
80 39 20 59 41.75 9.062 82.114
Creativity post-
test
80 1 1 2 1.50 .503 .253
Valid N
(listwise)
80
Null Hypothesis, Ho: there is no significant difference between creativity Pre-test and creativity
post-test. That is u1 – u2 = 0
Alternative Hypothesis: there is significant difference between creativity Pre-test and creativity
post-test. That is u1 – u2 is not equal to 0
b. .
Bar graph for Creativity Pre-test is given below. I observe that most of the students have a pre-
test score of 38. This is my mode here.

Bar graph for Creativity Post-test is given below. I observe that most of the students have a post-
test score of 55. This is my mode here.

c. .
Ho: there is no significant difference between means of creativity Pre-test and creativity post-
test. That is u1 – u2 = 0
H1: there is significant difference between means of creativity Pre-test and creativity post-test.
That is u1 – u2 =/= 0
3. .
a. .
Output obtained from SPSS after performing independent sample t test is shown below.
Group Statistics

Creativity post-
test
N Mean Std.
Deviation
Std. Error
Mean
Creativity pre-
test
Pre 40 40.15 8.304 1.313
Post 40 43.35 9.598 1.518
Independent Samples Test
Levene's
Test for
Equality
of...
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