1. Convert the following moisture content as indicated. Show your solutions. a. 18% wb to MCdb b. 26% wb to MCdb 15% db to MCwb d. 20% db to MCwb e. 24% db to MCwb 2. Determine the weight loss of a...


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1. Convert the following moisture content as indicated. Show your solutions.<br>a. 18% wb to MCdb<br>b. 26% wb to MCdb<br>15% db to MCwb<br>d. 20% db to MCwb<br>e. 24% db to MCwb<br>2. Determine the weight loss of a ton of paddy at 24% if dried to 14%. Correspondingly,<br>determine the price at different level. Considering price difference of P2.00/kg between<br>wet and dry. Make your conclusion from the above figures.<br>3. From a one hectare farm, 150 bags (50kg/bag) of palay were harvested with moisture<br>content of 26%MCwb. If it will be dry to 14%MC, determine how much water will be<br>removed from drying?<br>4. One hundred (100) bags of freshly harvested palay was dried to 14%MC and became<br>90 bags. Determine the fresh moisture content before drying.<br>5. Two tons of paddy with 22% moisture content on wet basis is to be dried to 13%<br>moisture content on dry basis. Calculate the weight of bone dry products and water<br>evaporated.<br>6. Determine the quantity of parboiled paddy with 40% moisture content on wet basis<br>required to produce 1 ton of product with 12% moisture content on wet basis. Work out<br>the problem on wet basis and check the answer using dry basis.<br>7. Draw a graph showing moisture content of grain on wet basis versus moisture content<br>on dry basis. Take the moisture content of grain on wet basis from 10% to 60% at equal<br>intervals of 5%.<br>c.<br>

Extracted text: 1. Convert the following moisture content as indicated. Show your solutions. a. 18% wb to MCdb b. 26% wb to MCdb 15% db to MCwb d. 20% db to MCwb e. 24% db to MCwb 2. Determine the weight loss of a ton of paddy at 24% if dried to 14%. Correspondingly, determine the price at different level. Considering price difference of P2.00/kg between wet and dry. Make your conclusion from the above figures. 3. From a one hectare farm, 150 bags (50kg/bag) of palay were harvested with moisture content of 26%MCwb. If it will be dry to 14%MC, determine how much water will be removed from drying? 4. One hundred (100) bags of freshly harvested palay was dried to 14%MC and became 90 bags. Determine the fresh moisture content before drying. 5. Two tons of paddy with 22% moisture content on wet basis is to be dried to 13% moisture content on dry basis. Calculate the weight of bone dry products and water evaporated. 6. Determine the quantity of parboiled paddy with 40% moisture content on wet basis required to produce 1 ton of product with 12% moisture content on wet basis. Work out the problem on wet basis and check the answer using dry basis. 7. Draw a graph showing moisture content of grain on wet basis versus moisture content on dry basis. Take the moisture content of grain on wet basis from 10% to 60% at equal intervals of 5%. c.
Moisture content wet basis - commercial<br>Ww<br>Ww<br>х 100% —<br>Wt<br>%MCwb<br>x 100%<br>Ww + Wd<br>2. Moisture content dry basis – research<br>Ww<br>Ww<br>x 100%<br>Wd<br>%MCdb<br>х 100%<br>Wt – Ww<br>Where:<br>Ww= weight of water<br>Wt = total weight<br>Wd = weight of dry matter – will not change at any level of moisture<br>Determination of water removed:<br>Wr = Wd (AMCdb)<br>Conversion<br>WB to DB<br>Ww/Wt<br>Ww<br>Wt<br>Ww<br>Ww<br>MCwb<br>%MCdb<br>Wd<br>Wt – Ww<br>Wt<br>1— Мсwb<br>Wt<br>DB to WB<br>Ww<br>Ww<br>Ww/Wd<br>MCdb<br>%MCwb<br>Wt<br>Ww + Wd<br>Ww<br>Wd<br>MCdb + 1<br>Wd + wd<br>Example: one hectare farm<br>100 bags (50kg/bag) at 24%MCwb<br>moisture content<br>after/during harvesting objective: to dry to 14%MC – MC safe for storage determine how much<br>water will be removed from drying and the final weight.<br>100 bags @ 50kg/bag = 5000 kg At 24%<br>Ww24%<br>Ww24% = MCwb (Wt)<br>0.24<br>= Ww24%+Wd<br>0.24(5000 kg) = 1,200 kg<br>Wd = Wt – Ww= 5,000 – 1,200 = 3,800 kg<br>At 14%<br>Ww14%<br>0.14<br>= Ww14%+Wd<br>Ww14%<br>0.14 = Ww14%+3,800 kg<br>Ww14 = 0.14(Ww14 + 3,800kg)<br>0.86WW14 = 0.14(3,800 kg) Ww14<br>= 618.6 kg<br>Wr = 1200 – 618.6 = 581.4kg/50 bags<br>Wf= 5,000 – 581.4 = 4,418 kg<br>11 bags<br>Convert wet basis(commercial) to dry basis (research)<br>MCdb24 = 31.6%<br>MCdb14 = 16.3%<br>Wr = Wd (AMCdb) = 3,800 (0.316 – 0.163) = 581.4kg<br>

Extracted text: Moisture content wet basis - commercial Ww Ww х 100% — Wt %MCwb x 100% Ww + Wd 2. Moisture content dry basis – research Ww Ww x 100% Wd %MCdb х 100% Wt – Ww Where: Ww= weight of water Wt = total weight Wd = weight of dry matter – will not change at any level of moisture Determination of water removed: Wr = Wd (AMCdb) Conversion WB to DB Ww/Wt Ww Wt Ww Ww MCwb %MCdb Wd Wt – Ww Wt 1— Мсwb Wt DB to WB Ww Ww Ww/Wd MCdb %MCwb Wt Ww + Wd Ww Wd MCdb + 1 Wd + wd Example: one hectare farm 100 bags (50kg/bag) at 24%MCwb moisture content after/during harvesting objective: to dry to 14%MC – MC safe for storage determine how much water will be removed from drying and the final weight. 100 bags @ 50kg/bag = 5000 kg At 24% Ww24% Ww24% = MCwb (Wt) 0.24 = Ww24%+Wd 0.24(5000 kg) = 1,200 kg Wd = Wt – Ww= 5,000 – 1,200 = 3,800 kg At 14% Ww14% 0.14 = Ww14%+Wd Ww14% 0.14 = Ww14%+3,800 kg Ww14 = 0.14(Ww14 + 3,800kg) 0.86WW14 = 0.14(3,800 kg) Ww14 = 618.6 kg Wr = 1200 – 618.6 = 581.4kg/50 bags Wf= 5,000 – 581.4 = 4,418 kg 11 bags Convert wet basis(commercial) to dry basis (research) MCdb24 = 31.6% MCdb14 = 16.3% Wr = Wd (AMCdb) = 3,800 (0.316 – 0.163) = 581.4kg
Jun 11, 2022
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