1- Convert the following C code to MIPS. Assume the address of base array is associated with Ss0, n is associated with $s1, position is associated with $t0, c is associated with $t1, d is associated...

Extracted text: 1- Convert the following C code to MIPS. Assume the address of base array is associated with Ss0, n is associated with $s1, position is associated with $t0, c is associated with $t1, d is associated with $t2, and swap is associated with $t3


Extracted text: for (c = 0; e < (n="" -="" 1):="" e++)="" position="" -="" e;="" for="" (d="" -="" c="" +="" 1;="">< n;="" d++)="" if="" (array(position)=""> array(d]) position - d; if (position !- c) array[c]; swap = array[c) - array position] - swap; array(position];