1. Consider the differential equation (which we saw on the wk 1 test) dy = y(y + 1)²(2 – y) dt Explain whether or not there can be a solution that satisfies both y(0) = 1 and y(5) = 4, and why or why...



Differential equation



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Consider the differential equation (which we saw on the wk 1 test)
??
?? = ?(? + 1)2(2 − ?)
Explain whether or not there can be a solution that satisfies both ?(0) = 1 and ?(5) = 4, and why or
why not.



1. Consider the differential equation (which we saw on the wk 1 test)<br>dy<br>= y(y + 1)²(2 – y)<br>dt<br>Explain whether or not there can be a solution that satisfies both y(0) = 1 and y(5) = 4, and why or<br>why not.<br>

Extracted text: 1. Consider the differential equation (which we saw on the wk 1 test) dy = y(y + 1)²(2 – y) dt Explain whether or not there can be a solution that satisfies both y(0) = 1 and y(5) = 4, and why or why not.

Jun 05, 2022
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