1. Consider a search graph in which every state has exactly 6 successors. Argue that there are exactly 1+6 + 62 + 63 + 6' paths of length at most 4 starting with the start state. In general, if d is a...


1. Consider a search graph in which every state has exactly 6 successors.<br>Argue that there are exactly 1+6 + 62 + 63 + 6' paths of length at<br>most 4 starting with the start state.<br>In general, if d is a positive integer, then there are 1+6+6²+6³+. +6d<br>paths of length at most d starting with the start state. You do not<br>have to prove this, but it should be plausible now.<br>Even more general, if b is the exact number of successors of each state,<br>then there are 1+b+b?...+ paths of length at most d starting from<br>the start state. Again, you do not have to prove this, but it should be<br>plausible now.<br>

Extracted text: 1. Consider a search graph in which every state has exactly 6 successors. Argue that there are exactly 1+6 + 62 + 63 + 6' paths of length at most 4 starting with the start state. In general, if d is a positive integer, then there are 1+6+6²+6³+. +6d paths of length at most d starting with the start state. You do not have to prove this, but it should be plausible now. Even more general, if b is the exact number of successors of each state, then there are 1+b+b?...+ paths of length at most d starting from the start state. Again, you do not have to prove this, but it should be plausible now.

Jun 09, 2022
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