1. Can a graph has a cut-vertex of degree one? Explain the reason for your answer. 2. Prove that: if S is a set of vertices in G, then 1[ 5,S ] = vES deg(v) — 2 e(G[S]). 3. Let G be a simple connected...

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1. Can a graph has a cut-vertex of degree one? Explain the reason for your answer.
2. Prove that: if S is a set of vertices in G, then 1[ 5,S ] =
vES
deg(v) — 2 e(G[S]).
3. Let G be a simple connected graph with blocks B1, B2, Bt. Prove that G has exactly
)(Bi) — t + 1 vertices. (Hint: Use induction on the number of blocks t)
4. Let G be a connected graph with an edge cut F. Prove that if G — F has exactly two components then the edge cut F is a bond. 5. Let G is a simple graph with A 3. Show that ki(G) = K(G).


Answered Same DayDec 22, 2021

Answer To: 1. Can a graph has a cut-vertex of degree one? Explain the reason for your answer. 2. Prove that: if...

Robert answered on Dec 22 2021
129 Votes
1.
A directed graph has two sets of cut-vertices of degree one.
Set of Sources, and Set of sink
s.
For an undirected graph,
Consider an undirected tree (conected and no cycles) od no of
vertices n. The root and lowest vertices have degree 1.
A bit of more rigorous proof follows, Suppose that all vertices as an
contradiction have a degree >=2.
Note that number of edges =n-1
No of degrees= 2(n-1)… Handshaking Lemma= 2n-2
No of vertices=n
Then at least two edges must have degree less than 2(since graph is
connected).
2.
|[S,S’]| is...
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