1 bị Suppose A = 1 -5 -3 x2 and b = b2 8. 16 x3 b3 The condition(s) on b1, b2 and b3 so that the system Ax = b is consistent is(are) %3D %3D (A) b3 = 8bị + 8b2, bị + b2 = 0 and b = 0 (B) b3 = -8b1 +...

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1<br>bị<br>Suppose A =<br>1<br>-5 -3<br>x2<br>and b =<br>b2<br>8.<br>16<br>x3<br>b3<br>The condition(s) on b1, b2 and b3 so that the system<br>Ax = b is consistent is(are)<br>%3D<br>%3D<br>(A) b3 = 8bị + 8b2, bị + b2 = 0 and b = 0<br>(B) b3 = -8b1 + -8b2<br>(C) The system is consistent for any b1, b2 and b3<br>(D) b3 = 8b1 + 8b2 and b1 + b2 = 0<br>%3D<br>(E) b3 = 8b1 + 8b2<br>

Extracted text: 1 bị Suppose A = 1 -5 -3 x2 and b = b2 8. 16 x3 b3 The condition(s) on b1, b2 and b3 so that the system Ax = b is consistent is(are) %3D %3D (A) b3 = 8bị + 8b2, bị + b2 = 0 and b = 0 (B) b3 = -8b1 + -8b2 (C) The system is consistent for any b1, b2 and b3 (D) b3 = 8b1 + 8b2 and b1 + b2 = 0 %3D (E) b3 = 8b1 + 8b2

Jun 04, 2022

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1 bị Suppose A = 1 -5 -3 x2 and b = b2 8. 16 x3 b3 The condition(s) on b1, b2 and b3 so that the system Ax = b is consistent is(are) %3D %3D (A) b3 = 8bị + 8b2, bị + b2 = 0 and b = 0 (B) b3 = -8b1 +...

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