(1) A 1KHZ alternating current has a peak value of 75 mA. i = Ip sin(360 f t)° (a) What is the time period T of this current ? Time Period, T = ms What will be the value of the instantaneous current i...

(1) A 1KHZ alternating current has a peak value of 75 mA.<br>i = Ip sin(360 f t)°<br>(a) What is the time period T of this current ?<br>Time Period, T =<br>ms<br>What will be the value of the instantaneous current i at the<br>following times, t: (b) 750 us (c) 2.4 ms (d) 4ms ?<br>(b) i =<br>(c) i=,<br>(d) i =<br>

Extracted text: (1) A 1KHZ alternating current has a peak value of 75 mA. i = Ip sin(360 f t)° (a) What is the time period T of this current ? Time Period, T = ms What will be the value of the instantaneous current i at the following times, t: (b) 750 us (c) 2.4 ms (d) 4ms ? (b) i = (c) i=, (d) i =

Jun 11, 2022

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(1) A 1KHZ alternating current has a peak value of 75 mA. i = Ip sin(360 f t)° (a) What is the time period T of this current ? Time Period, T = ms What will be the value of the instantaneous current i...

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