1 50804862342... 56 Advanced Calculus 15-18 Evaluate the double integral in two ways using iterated integrals: (a) viewing Ras a type I region, and (b) viewing R as a type II region. . 15. x? dA; R is...


1 50804862342...<br>56<br>Advanced Calculus<br>15-18 Evaluate the double integral in two ways using iterated<br>integrals: (a) viewing Ras a type I region, and (b) viewing R as<br>a type II region. .<br>15.<br>x? dA; R is the region bounded by y = 16/x, y = x,<br>and x = 8.<br>16.<br>xy dA; R is the region enclosed by y = 1, y = 2,<br>x = 0, and y = x.<br>17.<br>- 2y) dA; R is the region enclosed by the circle<br>x² + y? = 1.<br>18.<br>y dA; R is the region in the first quadrant enclosed<br>between the circle x? + y? = 25 and the line x + y = 5.<br>29-32 Use double integration to find the area of the plane re-<br>gion enclosed by the given curves. I<br>29. y = sin x and y = cos.x, for 0 < x < x/4.<br>30. у? — —х аnd 3y - х 3 4.<br>31. y² = 9 – x and y² = 9 – 9x.<br>32. y = coshx, y = sinh x, x = 0, and x = 1.<br>19-24 Evaluate the double integral. I<br>19.<br>x(1+ y?)-1/² dA; R is the region in the first quadrant<br>R<br>enclosed by y = x², y = 4, and x = 0.<br>20.<br>x cos y dA; R is the triangular region bounded by the<br>R<br>lines y = xr, y = 0, and x = A.<br>xy dA; R is the region enclosed by y = /x, y - -<br>ov / ov<br>ad y = 0.<br>22.<br>x dA; R is the region enclosed by y = sin¬' x,<br>R<br>x = 1/v2, und y = 0.<br>

Extracted text: 1 50804862342... 56 Advanced Calculus 15-18 Evaluate the double integral in two ways using iterated integrals: (a) viewing Ras a type I region, and (b) viewing R as a type II region. . 15. x? dA; R is the region bounded by y = 16/x, y = x, and x = 8. 16. xy dA; R is the region enclosed by y = 1, y = 2, x = 0, and y = x. 17. - 2y) dA; R is the region enclosed by the circle x² + y? = 1. 18. y dA; R is the region in the first quadrant enclosed between the circle x? + y? = 25 and the line x + y = 5. 29-32 Use double integration to find the area of the plane re- gion enclosed by the given curves. I 29. y = sin x and y = cos.x, for 0 < x="">< x/4.="" 30.="" у?="" —="" —х="" аnd="" 3y="" -="" х="" 3="" 4.="" 31.="" y²="9" –="" x="" and="" y²="9" –="" 9x.="" 32.="" y="coshx," y="sinh" x,="" x="0," and="" x="1." 19-24="" evaluate="" the="" double="" integral.="" i="" 19.="" x(1+="" y?)-1/²="" da;="" r="" is="" the="" region="" in="" the="" first="" quadrant="" r="" enclosed="" by="" y="x²," y="4," and="" x="0." 20.="" x="" cos="" y="" da;="" r="" is="" the="" triangular="" region="" bounded="" by="" the="" r="" lines="" y="xr," y="0," and="" x="A." xy="" da;="" r="" is="" the="" region="" enclosed="" by="" y="/x," y="" -="" -="" ov="" ov="" ad="" y="0." 22.="" x="" da;="" r="" is="" the="" region="" enclosed="" by="" y="sin¬'" x,="" r="" x="1/v2," und="" y="">

Jun 05, 2022
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