0 -5 9 1 -3 2 0 1 1 5z +9 (A) 3z + 2 (B) no solution is arbitrary(free) — 5у — 9 { -5y + 9z – 3 are arbitrary(free) %3| (C) (D) -3 Y, z is arbitrary(free) -5z +9 -5 %3D (E) -3z +2 (F) 9. %3D is...

Please help me with this math homework question. I really can not figure this out.

0 -5 9<br>1 -3 2<br>0 1<br>1<br>5z +9<br>(A)<br>3z + 2<br>(B)<br>no solution<br>is arbitrary(free)<br>— 5у — 9<br>{<br>-5y + 9z – 3<br>are arbitrary(free)<br>%3|<br>(C)<br>(D)<br>-3<br>Y, z<br>is arbitrary(free)<br>-5z +9<br>-5<br>%3D<br>(E)<br>-3z +2<br>(F)<br>9.<br>%3D<br>is arbitrary(free)<br>-3<br>3D 5у — 92 — 3<br>are arbitrary(free)<br>— 5у + 9<br>-3<br>(G)<br>(H)<br>Y, z<br>is arbitrary(free)<br>I| ||||<br>I||<br>I|||<br>I|||<br>

Extracted text: 0 -5 9 1 -3 2 0 1 1 5z +9 (A) 3z + 2 (B) no solution is arbitrary(free) — 5у — 9 { -5y + 9z – 3 are arbitrary(free) %3| (C) (D) -3 Y, z is arbitrary(free) -5z +9 -5 %3D (E) -3z +2 (F) 9. %3D is arbitrary(free) -3 3D 5у — 92 — 3 are arbitrary(free) — 5у + 9 -3 (G) (H) Y, z is arbitrary(free) I| |||| I|| I||| I|||

Jun 04, 2022

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0 -5 9 1 -3 2 0 1 1 5z +9 (A) 3z + 2 (B) no solution is arbitrary(free) — 5у — 9 { -5y + 9z – 3 are arbitrary(free) %3| (C) (D) -3 Y, z is arbitrary(free) -5z +9 -5 %3D (E) -3z +2 (F) 9. %3D is...

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