Review Assignment Problemsa.Identify and listall variables from the problem.b.Write the equation(s) you will use that arefound in the...

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Review Assignment Problems





















































a.

















Identify and list











all variables from the problem.















b.














W





rite the equation(s) you will use that are







found in the textbook





.


Do not use any other equations.















c.














S





ubstitute your variables into the equation.


YOU MUST INCLUDE UNITS IN ALL PLACES OF YOUR EQUATIONS.































d.

















You must show all of your work, even “simple” calculations.














During your calculations, please use 3 decimal places or 3 significant decimal places.


This does not apply to financial cost calculations.





























e.











Clearly identify your answer




with correct units


.






























ü











CORRECT METHOD:

































































x














INCORRECT METHOD:

















p2 = (W * a)/g + p1 = a^2 - Ap – μ = 0















































1.52.


The maximum pressure that can be developed for a certain fluid power cylinder is 15.0 MPa. Compute the required diameter for the piston if the cylinder must exert a force of 30 kN.



















































Known values:






































Governing equations:






































Calculations:























































































































1.86.


Glycerin has a specific gravity of 1.258. How much would 0.50 m3of glycerin weigh? What would be its mass?



















































Known values:































































































































































































Governing equations:































































































































































































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1.93.


A storage vessel for gasoline (sg = 0.68) is a vertical cylinder 10 m in diameter. If it is filled to a depth of 6.75 m, calculate the weight and mass of the gasoline.



























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3.48.


For the tank inFig. 3.22, compute the depth of the oil if the depth of the water is 2.80 m and the gage at the bottom of the tank reads 52.3 kPa(gage).






























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3.50.





Figure 3.22represents an oil storage drum that is open to the atmosphere at the top. Some water was accidentally pumped into the tank and settled to the bottom as shown in the figure. Calculate the depth of the waterh


2if the pressure gage at the bottom reads 158 kPa(gage). The total depthhT


= 18.0 m.






























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3.54.





Figure 3.23shows a closed tank that contains gasoline floating on water. Calculate the air pressure above the gasoline.






























































































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3.67.


Forthe compound manometer shown inFig. 3.31, calculate the pressure at point A.






























































































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4.14.


A rectangular gate is installed in a vertical wall of a reservoir, as shown in









Fig. 4.26








. Compute the magnitude of the resultant force on the gate and the location of the center of pressure. Also compute the force on each of the two latches shown.





























































































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4.17.


If the wall inFig. 4.29is 4 m long, calculate the total force on the wall due to the oil pressure. Also determine the location of the center of pressure and show the resultant force on the wall.






























































































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4.35.


For the water tank shown inFig. 4.43, compute the magnitude and location of the total force on the inclined wall.




































Known values:































































































































































































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4.52.


UseFig. 4.52. The surface is 1.50 m long.


Compute the magnitude of the horizontal component of the force and compute the vertical component of the force exerted by the fluid on that surface. Then compute the magnitude of the resultant force and its direction. Show the resultant force acting on the curved surface.



























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5.7.


A concrete block with a specific weight of 23.6 kN/m3is suspended by a rope in a solution with a specific gravity of 1.15. What is the volume of the concrete block if the tension in the rope is 2.67 kN?






























































































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5.9.


A steel cube 100 mm on a side weighs 80 N. We want to hold the cube in equilibrium under water by attaching a light foam buoy to it. If the foam weighs 470 N/m3, what is the minimum required volume of the buoy?






























































































Known values:































































































































































































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5.12.





Figure 5.20shows a cube floating in a fluid. Derive an expression relating the submerged depthX, the specific weight of the cube, and the specific weight of the fluid.






























































































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5.40.








A container for an emergency beacon is a rectangular shape 30.0 in wide, 40.0 in long, and 22.0 in high. Its center of gravity is 10.50 in above its base. The container weighs 250 lb. Will the box be stable with the 30.0-in by 40.0-in side parallel to the surface in plain water?





























































































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5.58.








If the barge in





Problem 5.57





is loaded with 240 000 lb of loose coal having an average density of 45 lb/ft3, how much of the barge would be below the water? Is it stable?





























Known values:































































































































































































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Answered Same DayJan 29, 2023

Answer To: Review Assignment Problemsa.Identify and listall variables...

Dr Shweta answered on Jan 30 2023
48 Votes
Solution:
Ans 1. A cold lubricating oil has greater dynamic viscosity than fresh water.
Ans 2. A fluid is said to be Newtonian if its viscosity remains constant, and its shear rate and stress bo
th remain constant.
Ans 3. Soap solution, butter, saliva, honey
Ans 4. The viscosity index, often known as the VI, is an arbitrary statistic that does not use any units to determine how much the viscosity of a fluid shifts in reaction to a change in temperature.
Ans 5. The viscosity of oil SAE 40, will be measured at 100 ͦ C temperature.
Ans 6. False because there are no negative values possible on the absolute pressure scale
Ans 7. False. The conventional sign for the scalar quantity known as pressure is the positive one. It is impossible for it to be negative.
Ans 8. Known values: P = 15 Mpa, F = 30 kN.
Governing equations: Pressure = Force/Area or A = F/P and area of piston = π/4d2
Calculations: Area of Piston = A = 30000/15000000
A = 0.002m3
As, A = π/4d2
d2 = 4 * 0.002/ π
d = 0.0606 m
Ans 9. Known values: specific gravity of glycerine = 1.258, V = 0.50 m3, density of water = 1000Kg/m3
Governing equations: Density of glycerine = Specific gravity of glycerine * Density of water,
Mass of glycerine = Density of glycerine * volume
Weight of glycerine = Mass of glycerine * acceleration
Calculations: ρg = 1.258 *1000 = 1258Kg/m3
mg = 1258 * 0.50 = 629 Kg
Wg = 629 *9.8 = 6170.49N
Ans 10. Known values: Specific gravity = 0.68, D = 10 m, H = 6.75 m
Governing equations: Mass = Density * volume
Volume = π/4d2* h
Density = Specific gravity * Density of water
Weight of gasoline = Mass *...
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